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For a first order reaction, show that the time required for `99%` completion is twice the time required for the completion of `90%` of reaction.

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For a first order reaction, show that the time required for 99% completion is twice the time required for the completion of 90% of reaction. Select the correct answer from above options

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Use direct relation, t99% t90% = log( 100 100-90 ) log( 100 100-90 ) = log100 log10 =2 ∴t99%=2t90%

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