Correct Answer - 0.135moleL-1
The unit of k(i.e.,s-1) shows that the reaction is of first order. Hence, k=
2.303
t
log
[A]initial
[A]left
=∴2.0×10-2s-1=
2.303
100s
log
1.0molL-1
[A]left
orlog[A]remainingorleft=-0.8684
∴[A]=Antilog(-0.8684)
=Antilog(--0.8684+1-1)
=Antilogbar(1).1316=0.1354mol L^(-1)