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Derive a Canonical POS expression for a Boolean function F,represented by the following truth table : 1A B C F0 0 0 01 0 0 10 1 0 11 1 0 00 0 1 01 0 1 10 1 1 0

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Derive a Canonical POS expression for a Boolean function F, represented by the following truth table : 1 A B C F 0 0 0 0 1 0 0 1 0 1 0 1 1 1 0 0 0 0 1 0 1 0 1 1 0 1 1 0 1 1 1 1 Select the correct answer from above options

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Answer: 10001 3au90 3579 45i9 4568 780 hip0 i89 yj89 y79. Explanation: 4 no makes this question answer hope it helps you my freind

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