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A series RLC circuit has R = 50 Ω, L = 0.01 H and C = 0.04 × 10^-6 F. System voltage is 100 V. At this frequency, the circuit impedance is? (a) 50 – j2.5 Ω (b) 50 – j2.8 Ω (c) 50 + j2.5 Ω (d) 50 + j2.8 Ω The question was posed to me during an interview. My query is from Problems of Series Resonance Involving Frequency Response of Series Resonant Circuit topic in section Resonance & Magnetically Coupled Circuit of Network Theory Select the correct answer from above options network theory questions and answers, network theory questions pdf, network theory question bank, network theory gate questions and answers pdf, mcq on network theory pdf, gate network theory questions and solutions, network theory mcq Test , ies network theory questions, Network theory Questions for GATE EC Exam, Network Theory MCQ (Multiple Choice Questions)

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The correct option is (a) 50 – j2.5 Ω Easy explanation: Z = R + j (ωL + \frac{1}{ωC}) = 50 + j \left(2π × 7937.81 × 0.01 – \frac{1}{2π×7937.81×0.04×10^{-6}}\right) = 50 – j2.5 Ω.

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