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Prove that √7 is an irrational number. Select the correct answer from above options

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Lets assume that √7 is rational number. ie √7=p/q. suppose p/q have common factor then we divide by the common factor to get √7 = a/b were a and b are co-prime number. that is a and b have no common factor. √7 =a/b co- prime number √7= a/b a=√7b squaring a²=7b² ..1 a² is divisible by 7 a=7c substituting values in 1 (7c)²=7b² 49c²=7b² 7c²=b² b²=7c² b² is divisible by 7 that is a and b have atleast one common factor 7. This is contridite to the fact that a and b have no common factor.This is happen because of our wrong assumption. √7 is irrational

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