n(S) = 8
(a) A: getting one Head = (HTH, HTT, TTH) = n(A) = 3 P(A) =
3
8
3
(b) B : getting atmost one head (TTT TTH, THT, HTT) n(B) = 4 P(B) =
4
8
4
=
1
2
1
(c) C : getting atleast two heads = {HHT, THH, HTH, HHH}, n(C) =
4
8
4
=
1
2
1
(d) D: first 2 are heads, E: 3 heads