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Tickets numbered from 1 to 20 are mixed up and a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 3 or 7? Select the correct answer from above options

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Given: Tickets are marked from 1 to 20 are mixed up. One ticket is picked at random. Required to find: Probability that the ticket bears a multiple of 3 or 7 Total number of cards is 20. And, the cards marked which is multiple of 3 or 7 are 3, 6, 7, 9, 12, 14, 15 and 18. So, the total number of cards marked multiple of 3 or 7 is 8. We know that Probability = Number of favourable outcomes/ Total number of outcomes Thus, the probability of drawing a card that is a multiple of 3 or 7 is 8/20 = 2/5

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