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It is known that a box of 200 electric bulbs contains 16 defective bulbs. One bulb is taken out at random from the box. What is the probability that the bulb drawn is (i) defective (ii) non-defective? Select the correct answer from above options

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Given: Total number of bulbs = 200 Number of defective bulbs = 16 (i) Let A be the event of getting a defective bulb Total number of defective bulbs = 16 So, P(getting defective bulbs) = P(A) = 16/200 = 2/25 (ii) Let B be the event of getting non-defective bulb So, P(getting non-defective bulb) = P(B) = 1 – P(A) = 1 – 2/25 = 23/25.

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