Question

Three coins are tossed 200 times and we get Three heads: 39 times; two heads: 58 times; One head: 67 times; o head: 36 times. When three coins are tossed at random, what is the probability of getting (i) 3 heads? (ii) 1 head? (iii) 0 head? (iv) 2 heads? Select the correct answer from above options

Answer 1

It is given that Number of trials = 200 Number of times 3 heads = 39 Number of times 2 heads = 58 Number of times 1 head = 67 Number of times 0 head = 36 Consider E1, E2, E3 and E4 as the events (i) So we get P (E1) = number of times 3 head/ number of trials By substituting the values P (E1) = 39/ 200 We get P (E1) = 0.195 (ii) So we get P (E2) = number of times 1 head/ number of trials By substituting the values P (E2) = 67/ 200 We get P (E2) = 0.335 (iii) So we get P (E3) = number of times 0 head/ number of trials By substituting the values P (E3) = 36/ 200 We get P (E3) = 0.18 (iv) So we get P (E4) = number of times 2 head/ number of trials By substituting the values P (E4) = 58/ 200 We get P (E4) = 0.29