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In a single throw of three dice, find the probability of getting a total of 17 or 18 Select the correct answer from above options

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Given: The dices are thrown. By using the formula, P (E) = favourable outcomes / total possible outcomes Total number of possible outcomes is 63 = 216 So, n (S) = 216 Let E be the event of getting total of 17 or 18 E = {(6, 6, 5) (6, 5, 6) (5, 6, 6) (6, 6, 6)} n (E) = 4 P (E) = n (E) / n (S) = 4 / 216 = 1/54

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