Given: Five cards are drawn from a pack of 52 cards.
By using the formula,
P (E) = favourable outcomes / total possible outcomes
Five cards are drawn at random,
Total possible outcomes are 52C5
n (S) = 2598960
(i) Let E be the event that exactly only one ace is present
n (E) = 4C148C4 = 778320
P (E) = n (E) / n (S)
= 778320 / 2598960
= 3243/10829
(ii) Let E be the event that at least one ace is present
E = {1 or 2 or 3 or 4 ace(s)}
n (E) = 4C148C4 + 4C248C3 + 4C348C2 + 4C448C1 = 886656
P (E) = n (E) / n (S)
= 886656 / 2598960
= 18472/54145
