Let
A be the event that home team will win the football game
B be the event that home team will tie the game
and C be the event that they will lose the game
then, we have
P(A) = 0.77, P(B) = 0.08
Now, we have to find the P( losing the game) or P(C)
We know that,
Sum of all Probabilities = 1
∴ P(A) + P(B) + P(C) = 1
⇒ 0.77 + 0.08 + P(C) = 1
⇒ P(C) = 1 – (0.77 + 0.08)
= 0.15
Ans. The probability that the home team will win an upcoming football game is 0.77, the probability that it will tie the game is 0.08, and the probability that it will lose the game is 0.15
