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Given, P(A) = 0.5, P(B) = 0.4, P(A∩B) = 0.3,

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Given, P(A) = 0.5, P(B) = 0.4, P(A∩B) = 0.3,then \(P\big(\frac{A'}{B'}\big)\) is equal to (a) \(\frac{1}{3}\) (b) \(\frac{1}{2}\) (c) \(\frac{2}{3}\) (d) \(\frac{3}{4}\) Select the correct answer from above options

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Answer: (C) 2 3 P( A′ B′ )= P(A′∩B′) P(B′) = P(A∩B)′ P(B′) = 1−P(A∪B) 1−P(B) = 1−[P(A)+P(B)−P(A∩B)] 1−P(B) = 1−[0.5+0.4−0.3] 1−0.4 = 0.4 0.6 = 2 3

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