When a die is thrown, all possible outcomes are 1,2,3,4,5,6.
Total number of possible outcomes = 6.
(i) Let `E_(1)` be the event of getting an even prime number.
Then, the favourable outcomes is 2 only.
Number of favourable outcomes = 1.
`:. ` P(getting an even prime number ) ` = P(E_(1)) = 1/6.`
(ii) Let `E_(2)` be the event of getting a multiple of 3.
Then, the favourable outcomes are 3 and 6.
Number of favourable outcomes = 2.
`:. ` P(getting a multiple of 3 ) ` = P(E_(2)) = 2/6 = 1/3`.
