When two coins are tossed simultaneously, all possible outcomes are HH, HT, TH, TT.
Total number of possible outcomes = 4.
Let E be the event of getting at least one head.
Then, E is the event of getting 1 head or 2 heads.
So, the favourable outcomes are HT, TH, HH.
Number of favourable outcomes = 3.
`:. ` P(getting at least one head ) ` =P(E) = 3/4`.