For three events
A
,
B
and
C
,
P
(Exactly one of
A
or
B
occurs)
=
P
(Exactly one of
B
or
C
occurs)
=
P
(Exactly one of
C
or
A
occurs)
=
1
4
and
P
(All the three events occur simultaneously)
=
1
6
.
Then the probability that at least one of the events occurs, is :
7
64
(2)
3
16
(3)
7
32
(4)
7
16
A.
7
32
B.
7
16
C.
7
64
D.
3
16
Select the correct answer from above options