Correct Answer - B
We have,
P
(
A
∩
B
)
=
1
6
and
(
¯¯¯
A
∩
¯¯¯
B
)
=
1
3
P
⇒
P
(
A
)
P
(
B
)
=
1
6
and
P
(
¯¯¯
A
)
P
(
¯¯¯
B
)
=
1
3
⇒
⇒
x
y
=
1
6
and
(
1
−
x
)
(
1
−
y
)
=
1
3
⇒
, where P(A)=x, P(B)=y
⇒
x
y
=
1
6
and
1
−
x
−
y
+
1
6
=
1
3
⇒
⇒
x
y
=
1
6
and
x
+
y
=
5
6
⇒
⇒
x
=
1
2
and
y
=
1
3
or
x
=
1
3
and
y
=
1
2
⇒