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Three persons A, B and C speak at a function along with 5 other persons. If the persons speak at random, find the probability that A speaks before B a

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Three persons A, B and C speak at a function along with 5 other persons. If the persons speak at random, find the probability that A speaks before B and B speaks before C A. 3 / 8 3 B. 1 / 6 1 C. 3 / 5 3 D. none of these Select the correct answer from above options

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Correct Answer - B The total number of ways in which 8 persons can speak is . 8 P 8 = 8 ! . The number of ways in which A, B and C can be arranged in the specified speaking order is . 8 C 3 . . There are 5! Ways in which the other five can speak. So, Favourable number of ways = . 8 C 3 × 5 ! = Hence, required probability = . 8 C 3 × 5 ! 8 ! = 1 6 =

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