Correct Answer - A
We have,
Number of diagonals of a hexagon
−
.
6
C
2
−
6
=
9
-
Number of ways of selecting two diagonals
=
.
9
C
2
=
36
=
Number of ways of selecting two intersecting diagonals
= Number of ways of selecting four vertices of the hexagon
=
.
6
C
4
=
15
=
Hence, required probability
=
15
36
=
5
12
=