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In a convex hexagon two diagonals are drawn at random. The probability that the diagonals intersect at an interior point of the hexagon is A. 5/12 B. 7/12 C. 2/5 D. none of these Select the correct answer from above options

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Correct Answer - A We have, Number of diagonals of a hexagon − . 6 C 2 − 6 = 9 - Number of ways of selecting two diagonals = . 9 C 2 = 36 = Number of ways of selecting two intersecting diagonals = Number of ways of selecting four vertices of the hexagon = . 6 C 4 = 15 = Hence, required probability = 15 36 = 5 12 =

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