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Twelve balls are distribute among three boxes. The probability that the first box contains three balls is `(110)/9(2/3)^(10)` b. `(110)/9(2/3)^(10)` c

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Twelve balls are distribute among three boxes. The probability that the first box contains three balls is `(110)/9(2/3)^(10)` b. `(110)/9(2/3)^(10)` c. `(^(12)C_3)/(12^3)xx2^9` d. `(^(12)C_3)/(3^(12))` Select the correct answer from above options

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`x+ y = 9` `P=.^9C_3 (1/3)^3(2/3)^9` `= (12 xx 11 xx 10)/3 xx 1/3^3 xx (2/3)^9` `= 220/3^3 xx (2/3)^9` `= 55/3 xx 2^2/3^2 xx (2/3)^9` `= 55/3 xx (2/3)^11` option 1 is correct

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