There are total `20` tickets numbered from `1` to `20`.
So, `10` tickets has even number and `10` tickets have odd numbers.
Now, probability of drawing a ticket that has even number ` = 10/20 = 1/2`
Now, there are total `19` tickets and `10` odd tickets are available.
`:.` Probability of drawing a ticket that has odd number `= 10/19`
`:.` Required probability ` = 1/2**10/19 = 5/19`