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A die is tossed thrice. Find the probability of getting an odd number at least once.

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P(atleast one odd) = 1 - P(all even) = 1 - p(even 1st) p(even 2nd)p(even 3rd)` `= 1 - (3/6)(3/6)(3/6)` `=1- (1/2)^3` `= 1-1/8 = 7/8` answer

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