Correct Answer - `2/15`
Let A = event that the sum of two numbers appeared is 5, and B = event that the two dice show different numbers.
The, `A={(2, 3), (3, 2), (1, 4), (4, 1)}`.
Thus, `n(A)=4, n(B)=30, A nn B=A` and so `n(A nn B)=n(A)=4`.
`:.` the required probability `=P(A//B)=(n (A nn B))/(n(B))=4/30=2/15`.