Correct Answer - A::B::C
We know that,
P(A∩B)=P(A)+P(B)-P(A∪B)
Also, P(A∪B)≤1
∴P(A∩B)min, where P(A∪B)max=1
⇒P(A∩B)≥P(A)+P(B)-1
∴ Option (a) is true.
Again, P(A∪B)≥0
∴P(A∩B)max, when P(A∪B)min=0
⇒P(A∩B)≤P(A)+P(B)
∴Option (b) is true.
Also, P(A∩B)=P(A)+P(B)-P(A∪B), Thus, (c ) is also correct.
Hence, (a),(b),(c ) are correct options.