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Find the potential of V = 60sin θ/r^2 at P(3,60,25)

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Find the potential of V = 60sin θ/r^2 at P(3,60,25) (a) 5.774 (b) 6.774 (c) 7.774 (d) 8.774 I got this question during an interview for a job. This is a very interesting question from Electric Potential in division Electrostatic Fields of Electromagnetic Theory Select the correct answer from above options Electromagnetic Theory questions and answers, Electromagnetic Theory questions pdf, Electromagnetic Theory question bank, Electromagnetic Theory questions and answers pdf, mcq on Electromagnetic Theory pdf,electromagnetic theory book pdf,electromagnetic theory pdf notes,electromagnetic theory lecture notes,electromagnetic theory of light,maxwell electromagnetic theory,electromagnetic theory proposed by,electromagnetic theory engineering physics,electromagnetic theory nptel

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The correct answer is (a) 5.774 Explanation: V = 60sin θ/r^2, put r = 3m, θ = 60 and φ = 25, V = 60 sin 60/3^2 = 5.774 volts.

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