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In electric fields, D= ε E. The correct expression which is analogous in magnetic fields will be (a) H = μ B (b) B = μ H (c) A = μ B (d) H = μ A This question was addressed to me in class test. I would like to ask this question from Real Time Applications topic in chapter Electrostatic Fields of Electromagnetic Theory Select the correct answer from above options Electromagnetic Theory questions and answers, Electromagnetic Theory questions pdf, Electromagnetic Theory question bank, Electromagnetic Theory questions and answers pdf, mcq on Electromagnetic Theory pdf,electromagnetic theory book pdf,electromagnetic theory pdf notes,electromagnetic theory lecture notes,electromagnetic theory of light,maxwell electromagnetic theory,electromagnetic theory proposed by,electromagnetic theory engineering physics,electromagnetic theory nptel

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Right option is (b) B = μ H For explanation: In electric fields, the flux density is a product of permittivity and field intensity. Similarly, for magnetic fields, the magnetic flux density is the product of permeability and magnetic field intensity, given by B= μ H.

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