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Find the electric field if the surface density at the boundary of air is 10^-9. (a) 12π (b) 24π (c) 36π (d) 48π I had been asked this question in an online interview. My question is taken from Boundary Conditions topic in division Electric Fields in Material Space of Electromagnetic Theory Select the correct answer from above options Electromagnetic Theory questions and answers, Electromagnetic Theory questions pdf, Electromagnetic Theory question bank, Electromagnetic Theory questions and answers pdf, mcq on Electromagnetic Theory pdf,electromagnetic theory book pdf,electromagnetic theory pdf notes,electromagnetic theory lecture notes,electromagnetic theory of light,maxwell electromagnetic theory,electromagnetic theory proposed by,electromagnetic theory engineering physics,electromagnetic theory nptel

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Right option is (c) 36π The best I can explain: It is the conductor-free space boundary. At the boundary, E = ρ/εo. Put ρ = 10^-9 and εo = 10^-9/36π. We get E = 36π units.

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