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Find the electric field when the velocity of the field is 12m/s and the flux density is 8.75 units. (a) 510 (b) 105 (c) 150 (d) 165 The question was asked in semester exam. Asked question is from Magnetic Force and Lorentz Force in chapter Magnetic Forces and Materials of Electromagnetic Theory Select the correct answer from above options Electromagnetic Theory questions and answers, Electromagnetic Theory questions pdf, Electromagnetic Theory question bank, Electromagnetic Theory questions and answers pdf, mcq on Electromagnetic Theory pdf,electromagnetic theory book pdf,electromagnetic theory pdf notes,electromagnetic theory lecture notes,electromagnetic theory of light,maxwell electromagnetic theory,electromagnetic theory proposed by,electromagnetic theory engineering physics,electromagnetic theory nptel

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Right answer is (b) 105 For explanation: The electric field intensity is the product of the velocity and the magnetic flux density ie, E = v x B = 12 x 8.75 = 105 units.

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