Question

Find the ratio of refractive index of medium 2 to that of medium 1, when the Brewster angle is 60 degree. (a) 0.707 (b) 1.5 (c) 0.866 (d) 1.732 I have been asked this question in semester exam. This is a very interesting question from Brewster Angle in section EM Wave Propagation of Electromagnetic Theory Select the correct answer from above options Electromagnetic Theory questions and answers, Electromagnetic Theory questions pdf, Electromagnetic Theory question bank, Electromagnetic Theory questions and answers pdf, mcq on Electromagnetic Theory pdf,electromagnetic theory book pdf,electromagnetic theory pdf notes,electromagnetic theory lecture notes,electromagnetic theory of light,maxwell electromagnetic theory,electromagnetic theory proposed by,electromagnetic theory engineering physics,electromagnetic theory nptel

Answer 1

Right option is (d) 1.732 For explanation I would say: The tangent of the Brewster angle is the ratio of the medium 2 permittivity to the medium 1 permittivity. Thus tan θb = (n2/n1). Given that θb = 60 degree, the ratio n2/n1 will be tan 60 = 1.732.