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An inductor of 3mH has a current i = 5(1 – e^-5000t). Find the corresponding maximum energy stored. (a) 37.5 mJ (b) 375 J (c) 37.5 kJ (d) 3.75 mJ This question was addressed to me in class test. The doubt is from Basic Network Concepts in section Circuit Elements and Kirchhoff’s Laws of Network Theory Select the correct answer from above options network theory questions and answers, network theory questions pdf, network theory question bank, network theory gate questions and answers pdf, mcq on network theory pdf, gate network theory questions and solutions, network theory mcq Test , ies network theory questions, Network theory Questions for GATE EC Exam, Network Theory MCQ (Multiple Choice Questions)

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Correct choice is (a) 37.5 mJ Best explanation: Given L = 3 mH, i = 5(1 – e^-5000t) V = L \(\frac{di}{dt} = 3 × 10^{-3} \frac{d}{dt}[5(1-e^{-5000t})] = 75 e^{-5000t}\) I = i(∞) = 5(1 – e^-∞) = 5 A E = \(\frac{1}{2}\) LI^2 = 0.5 × 3 × 10^-3 × 5^2 = 37.5 mJ.

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