Question

For the circuit shown in the figure below, the Norton Resistance looking into X-Y is __________ (a) 2 Ω (b) \frac{2}{3} (c) \frac{5}{3} (d) 2 Ω I got this question in an international level competition. My enquiry is from Norton’s Theorem Involving Dependent and Independent Sources topic in division Useful Theorems in Circuit Analysis of Network Theory Select the correct answer from above options network theory questions and answers, network theory questions pdf, network theory question bank, network theory gate questions and answers pdf, mcq on network theory pdf, gate network theory questions and solutions, network theory mcq Test , ies network theory questions, Network theory Questions for GATE EC Exam, Network Theory MCQ (Multiple Choice Questions)

Answer 1

The correct choice is (d) 2 Ω The explanation is: R_N = \frac{V_{OC}}{I_{SC}} VN = VOC Applying KCL at node A, \frac{2I-V_N}{1} + 2 = I + \frac{V_N}{2} Or, I = \frac{V_N}{1} Putting, 2VN – VN + 2 = VN + \frac{V_N}{2} Or, VN = 4 V. ∴ RN = 4/2 = 2Ω.