Question

In the circuit given below, the current in the resistance 20 Ω(far end) is _________ (a) 8.43 A (b) 5.67 A (c) 1.43 A (d) 2.47 A I got this question during an interview. Asked question is from Advanced Problems on Reciprocity Theorem topic in portion Useful Theorems in Circuit Analysis of Network Theory Select the correct answer from above options network theory questions and answers, network theory questions pdf, network theory question bank, network theory gate questions and answers pdf, mcq on network theory pdf, gate network theory questions and solutions, network theory mcq Test , ies network theory questions, Network theory Questions for GATE EC Exam, Network Theory MCQ (Multiple Choice Questions)

Answer 1

Right answer is (c) 1.43 A Explanation: Equivalent Resistance REQ = 20 + [30 || (20 + (20||20))] = 20 + [30 || (20 + \frac{20×20}{20+20})] = 20 + [30 || (20+10)] = 20 + [30 || 30] = 20 + \frac{30 × 30}{30+30} = 20 + 15 = 35 Ω The current drawn by the circuit = \frac{200}{35} = 5.71 A Now, by using current division rule, we get, I2Ω = 1.43 A.