Question

Find the Norton’s current passing through ‘ab’ in the circuit shown below. (a) 4.16∠126.8⁰ (b) 5.16∠126.8⁰ (c) 5.16∠-126.8⁰ (d) 4.16∠-126.8⁰ I had been asked this question by my school teacher while I was bunking the class. I want to ask this question from Norton’s Theorem in portion Steady State AC Analysis of Network Theory Select the correct answer from above options network theory questions and answers, network theory questions pdf, network theory question bank, network theory gate questions and answers pdf, mcq on network theory pdf, gate network theory questions and solutions, network theory mcq Test , ies network theory questions, Network theory Questions for GATE EC Exam, Network Theory MCQ (Multiple Choice Questions)

Answer 1

Right answer is (d) 4.16∠-126.8⁰ Easy explanation: The Norton’s current is equal to the current passing through the short circuit between the points a and b. The Norton’s current is I=(10∠0^o)/(3∠90^o)+(5∠90^o)/(2∠-90^o) =4.16∠-126.8^oA.