Question

The circuit shown in the figure below will act as an ideal source with respect to terminal A and B when the frequency is ___________ (a) Zero (b) 1 rad/s (c) 4 rad/s (d) 16 rad/s The question was posed to me by my college professor while I was bunking the class. My question comes from Advanced Problems on Resonance in section Resonance & Magnetically Coupled Circuit of Network Theory Select the correct answer from above options network theory questions and answers, network theory questions pdf, network theory question bank, network theory gate questions and answers pdf, mcq on network theory pdf, gate network theory questions and solutions, network theory mcq Test , ies network theory questions, Network theory Questions for GATE EC Exam, Network Theory MCQ (Multiple Choice Questions)

Answer 1

The correct answer is (c) 4 rad/s To explain: Z(s) t = \frac{(Ls)\frac{1}{Cs}}{Ls + \frac{1}{Cs}} = \frac{Ls}{LCs^2+1} Putting s = jω, we get, Z (jω) = \frac{jωL}{1 -LCω^2} For ideal current source, Z (jω) = ∞ Or, 1 – LCω^2 = 0 Or, ω = \frac{1}{\sqrt{LC}} = \frac{1}{\sqrt{\frac{1}{16}×1}} = 4 rad/s.