Question

A three-phase balanced delta connected load of (4+j8) Ω is connected across a 400V, 3 – Ø balanced supply. Determine the phase current IR. Assume the phase sequence to be RYB. (a) 44.74∠-63.4⁰A (b) 44.74∠63.4⁰A (c) 45.74∠-63.4⁰A (d) 45.74∠63.4⁰A The question was posed to me in exam. I want to ask this question from Three-Phase Balanced Circuits in chapter Polyphase Circuits of Network Theory Select the correct answer from above options network theory questions and answers, network theory questions pdf, network theory question bank, network theory gate questions and answers pdf, mcq on network theory pdf, gate network theory questions and solutions, network theory mcq Test , ies network theory questions, Network theory Questions for GATE EC Exam, Network Theory MCQ (Multiple Choice Questions)

Answer 1

The correct option is (a) 44.74∠-63.4⁰A The explanation is: Taking the line voltage VRY = V∠0⁰ as a reference VRY = 400∠0⁰V, VYB = 400∠-120⁰V and VBR = 400∠-240⁰V. Impedance per phase = (4+j8) Ω = 8.94∠63.4⁰Ω. Phase current IR = (400∠0^o)/(8.94∠63.4^o )= 44.74∠-63.4⁰A.