Question

The complete solution of the current in the sinusoidal response of R-L circuit is? (a) i = e^-t(R/L)[V/√(R^2+(ωL)^2) cos⁡(θ-tan^-1)⁡(ωL/R))]+V/√(R^2+(ωL)^2) cos⁡(ωt+θ-tan^-1)⁡(ωL/R)) (b) i = e^-t(R/L)[-V/√(R^2+(ωL)^2) cos⁡(θ-tan^-1)(ωL/R))]-V/√(R^2+(ωL)^2) cos⁡(ωt+θ-tan^-1)⁡(ωL/R)) (c) i = e^-t(R/L)[V/√(R^2+(ωL)^2) cos⁡(θ-tan^-1)⁡(ωL/R))]-V/√(R^2+(ωL)^2) cos⁡(ωt+θ-tan^-1)⁡(ωL/R)) (d) i = e^-t(R/L)[-V/√(R^2+(ωL)^2) cos⁡(θ-tan^-1)⁡(ωL/R))]+V/√(R^2+(ωL)^2) cos⁡(ωt+θ-tan^-1)⁡(ωL/R)) The question was asked in final exam. This intriguing question originated from Sinusoidal Response of an R-L Circuit topic in portion Transients of Network Theory Select the correct answer from above options network theory questions and answers, network theory questions pdf, network theory question bank, network theory gate questions and answers pdf, mcq on network theory pdf, gate network theory questions and solutions, network theory mcq Test , ies network theory questions, Network theory Questions for GATE EC Exam, Network Theory MCQ (Multiple Choice Questions)

Answer 1

Correct answer is (d) i = e^-t(R/L)[-V/√(R^2+(ωL)^2) cos⁡(θ-tan^-1)⁡(ωL/R))]+V/√(R^2+(ωL)^2) cos⁡(ωt+θ-tan^-1)⁡(ωL/R)) Explanation: The complete solution for the current becomes i = e^-t(R/L)[-V/√(R^2+(ωL)^2) cos⁡(θ-tan^-1)⁡(ωL/R))]+V/√(R^2+(ωL)^2)cos⁡(ωt+θ-tan^-1)⁡(ωL/R)).