Question

Find the function f3 (t) from the time t = 3 to 4 sec. (a) (20t – 40) [u (t-3) – u (t-4)] (b) (20t + 40) [u (t-3) – u (t-4)] (c) (20t + 40) [u (t-3) + u (t-4)] (d) (20t – 40) [u (t-3) + u (t-4)] I got this question during an interview. This question is from Definition of the Laplace Transform topic in section Intoduction to the Laplace Transform of Network Theory Select the correct answer from above options network theory questions and answers, network theory questions pdf, network theory question bank, network theory gate questions and answers pdf, mcq on network theory pdf, gate network theory questions and solutions, network theory mcq Test , ies network theory questions, Network theory Questions for GATE EC Exam, Network Theory MCQ (Multiple Choice Questions)

Answer 1

Correct answer is (a) (20t – 40) [u (t-3) – u (t-4)] For explanation: From the graph, f3 (t) = 20t – 40 for 3 < t < 4. In terms of unit step function, f3 (t) = (20t – 40) [u (t-3) – u (t-4)]. This function turn off at t = 3, turn off at t = 4.