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For the circuit given below, the value of g11 and g21 are _________________ (a) g11 = 0.0667 – j0.0333 Ω, g21 = 0.8 + j0.4 Ω (b) g11 = -0.0667 – j0.0333 Ω, g21 = -0.8 – j0.4 Ω (c) g11 = 0.0667 + j0.0333 Ω, g21 = 0.8 + j0.4 Ω (d) g11 = -0.0667 + j0.0333 Ω, g21 = 0.8 – j0.4 Ω I had been asked this question during an online interview. This intriguing question comes from Advanced Problems Involving Parameters topic in portion Two-Port Networks of Network Theory Select the correct answer from above options network theory questions and answers, network theory questions pdf, network theory question bank, network theory gate questions and answers pdf, mcq on network theory pdf, gate network theory questions and solutions, network theory mcq Test , ies network theory questions, Network theory Questions for GATE EC Exam, Network Theory MCQ (Multiple Choice Questions)

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Right option is (c) g11 = 0.0667 + j0.0333 Ω, g21 = 0.8 + j0.4 Ω For explanation I would say: V1 = (12-j6) I1 Or, g11 = \frac{I_1}{V_1} = \frac{1}{12-j6} = 0.0667 + j0.0333 Ω g21 = \frac{V_2}{V_1} = \frac{12I_1}{(12-j6) I_1} = \frac{2}{2-j} = 0.8 + j0.4 Ω.

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