Question

In the circuit given below, the equivalent capacitance is ______________ (a) \frac{C}{4} (b) \frac{5C}{13} (c) \frac{5C}{2} (d) 3C This question was addressed to me in unit test. This is a very interesting question from Series-Series Connection of Two Port Network in chapter Two-Port Networks of Network Theory Select the correct answer from above options network theory questions and answers, network theory questions pdf, network theory question bank, network theory gate questions and answers pdf, mcq on network theory pdf, gate network theory questions and solutions, network theory mcq Test , ies network theory questions, Network theory Questions for GATE EC Exam, Network Theory MCQ (Multiple Choice Questions)

Answer 1

Correct choice is (b) \frac{5C}{13} Easy explanation: The equivalent capacitance by applying the concept of series-parallel combination of the capacitance is, \frac{1}{C_{EQ}} = \frac{1}{C} + \frac{1}{C} + \frac{1}{5C/3} = \frac{1}{C} + \frac{1}{C} + \frac{3}{5C} = \frac{1}{C}(\frac{5+5+3}{5}) Or, CEQ = \frac{5C}{13} 123 c Energy delivered during talk time E = ∫ V(t)I(t) dt Given, I (t) = 2 A = constant = 2 ∫ V(t)dt = 2 × Shaded area = 2 × \frac{1}{2} × (10 + 12) × 60 × 10 = 13.2 kJ.