Question

For a T shaped network, if the Short-circuit admittance parameters are y11, y12, y21, y22, then y21 in terms of Transmission parameters can be expressed as ________ (a) Y21 = \frac{D}{B} (b) Y21 = \frac{C-A}{B} (c) Y21 = – \frac{1}{B} (d) Y21 = \frac{A}{B} I had been asked this question in my homework. My question is based upon Relation between Transmission Parameters with Short Circuit Admittance and Open Circuit Impedance Parameters topic in chapter Two-Port Networks of Network Theory Select the correct answer from above options network theory questions and answers, network theory questions pdf, network theory question bank, network theory gate questions and answers pdf, mcq on network theory pdf, gate network theory questions and solutions, network theory mcq Test , ies network theory questions, Network theory Questions for GATE EC Exam, Network Theory MCQ (Multiple Choice Questions)

Answer 1

Correct answer is (c) Y21 = – \frac{1}{B} Easy explanation: We know that, V1 = AV2 – BI2 ……… (1) I1 = CV2 – DI2 …………… (2) And, I1 = y11 V1 + y12 V2 ……… (3) I2 = y21 V1 + y22 V2 ………. (4) Now, (1) and (2) can be rewritten as, I2 = \frac{A}{B}V_2 – \frac{1}{B}V_1 …………. (5) And I1 = CV2 – D \left(\frac{A}{B}V_2 – \frac{1}{B}V_1\right) = \frac{D}{B}V_1 + \left(C-\frac{A}{B}\right) V_2 …………… (6) Comparing equations (3), (4) and (5), (6), we get, y11 = \frac{D}{B} y12 = \frac{C-A}{B} y21 = – \frac{1}{B} y22 = \frac{A}{B} .