Question

For a T-network if the Open circuit Impedance parameters are z11, z12, z21, z22, then z11 in terms of Transmission parameters can be expressed as ____________ (a) z11 = \frac{D’}{C’} (b) z11 = \frac{1}{C’} (c) z11 = \left(\frac{A’ D’}{C’} – B’\right) (d) z11 = \frac{A’}{C’} This question was posed to me by my college professor while I was bunking the class. Question is taken from Relation between Transmission Parameters with Short Circuit Admittance and Open Circuit Impedance Parameters in portion Two-Port Networks of Network Theory Select the correct answer from above options network theory questions and answers, network theory questions pdf, network theory question bank, network theory gate questions and answers pdf, mcq on network theory pdf, gate network theory questions and solutions, network theory mcq Test , ies network theory questions, Network theory Questions for GATE EC Exam, Network Theory MCQ (Multiple Choice Questions)

Answer 1

The correct option is (a) z11 = \frac{D’}{C’} Best explanation: We know that, V1 = z11 I1 + z12 I2 …………. (1) V2 = z21 I1 + z22 I2 ……………. (2) And V2 = A’V1 – B’I1 ……… (3) I2 = C’V1 – D’I1 …………… (4) Rewriting (3) and (4), we get, V2 = A’ \left(\frac{D’}{C’} I_1 + \frac{1}{C’} I_2\right) – B’I_1 = \left(\frac{A’ D’}{C’} – B’\right) I_1 + \frac{A’}{C’} I_2 ………… (5) And V1 = \frac{D’}{C’} I_1 + \frac{1}{C’} I_2 ………….. (6) Comparing (1), (2) and (5), (6), we get, z11 = \frac{D’}{C’} z12 = \frac{1}{C’} z21 = \left(\frac{A’ D’}{C’} – B’\right) z22 = \frac{A’}{C’} .