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For the circuit given below, the value of the z12 parameter is ___________ (a) z12 = 1 Ω (b) z12 = 4 Ω (c) z12 = 1.667 Ω (d) z12 = 2.33 Ω The question was posed to me in an online quiz. My query is from Advanced Problems on Two Port Network in chapter Two-Port Networks of Network Theory Select the correct answer from above options network theory questions and answers, network theory questions pdf, network theory question bank, network theory gate questions and answers pdf, mcq on network theory pdf, gate network theory questions and solutions, network theory mcq Test , ies network theory questions, Network theory Questions for GATE EC Exam, Network Theory MCQ (Multiple Choice Questions)

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Right choice is (a) z12 = 1 Ω To explain I would say: z11 = \frac{V_1}{I_1} = 1 + 6 || (4+2) = 4Ω I0 = \frac{1}{2} I_1 V2 = 2I0 = I1 z21 = \frac{V_2}{I_1} = 1Ω z22 = \frac{V_2}{I_2} = 2 || (4+6) = 1.667Ω So, I’0 = \frac{2}{2+10}I_2 = \frac{1}{6}I_2 V1 = 6I’0 = I2 z12 = \frac{V_1}{I_2} = 1Ω Hence, [z] = [4:1; 1:1.667] Ω.

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