Question

In the circuit given below, the KVL for first loop is ___________ (a) V (t) = R1i1 + L1 \frac{di_1}{dt} + M \frac{di_2}{dt} (b) V (t) = R1i1 – L1 \frac{di_1}{dt} – M \frac{di_2}{dt} (c) V (t) = R1i1 + L1 \frac{di_1}{dt} – M \frac{di_2}{dt} (d) V (t) = R1i1 – L1 \frac{di_1}{dt} + M \frac{di_2}{dt} I have been asked this question in examination. My query is from Advanced Problems Involving Complex Circuit Diagram topic in chapter Network Theory and Complex Circuit Diagram of Network Theory Select the correct answer from above options network theory questions and answers, network theory questions pdf, network theory question bank, network theory gate questions and answers pdf, mcq on network theory pdf, gate network theory questions and solutions, network theory mcq Test , ies network theory questions, Network theory Questions for GATE EC Exam, Network Theory MCQ (Multiple Choice Questions)

Answer 1

Right answer is (c) V (t) = R1i1 + L1 \frac{di_1}{dt} – M \frac{di_2}{dt} To explain: We know that, in general, the KVL is of the form V (t) = R1i1 + L1 \frac{di_1}{dt} + M \frac{di_2}{dt} But here, M term is negative because i1, is entering the dotted terminal and i2, is leaving the dotted terminal. So, V (t) = R1i1 + L1 \frac{di_1}{dt} – M \frac{di_2}{dt} .