Answer: A) 1 10/11 minutes past 2
Explanation:
Since, in one hour, two hands of a clock coincide only once, so, there will be value.
Required time T = 211(H×30 + Ao)T = 211H×30 + Ao minutes past H.
Here H - initial position of hour hand = 2 (since 2 O'clock)
A° = Required angle = 0° (Since it coincides)
T = 211(2×30 + 0o)T = 2112×30 + 0o minutes past 2
=> 1101111011 minutes past 2