how to remove last comma from line in bash using "sed or awk"

Question

Hi I want to remove last comma from a line. For example: Input: This,is,a,test Desired Output: This,is,a test I am able to remove last comma if its also the last character of the string using below command: (However this is not I want) echo "This,is,a,test," |sed 's/,$//' This,is,a,test Same command does not work if there are more characters past last comma in line. echo "This,is,a,test" |sed 's/,$//' This,is,a,test I am able to achieve the results using dirty way by calling multiple commands, any alternative to achieve the same using awk or sed regex ?(This is I want) echo "This,is,a,test" |rev |sed 's/,/ /' |rev This,is,a test JavaScript questions and answers, JavaScript questions pdf, JavaScript question bank, JavaScript questions and answers pdf, mcq on JavaScript pdf, JavaScript questions and solutions, JavaScript mcq Test , Interview JavaScript questions, JavaScript Questions for Interview, JavaScript MCQ (Multiple Choice Questions)

Answer 1

$ echo "This,is,a,test" | sed 's/\(.*\),/\1 /' This,is,a test $ echo "This,is,a,test" | perl -pe 's/.*\K,/ /' This,is,a test In both cases, .* will match as much as possible, so only the last comma will be changed.