Instanciate concrete class a generic method in scala

Question

I have a generic method which a generic type parameter T which is a subclass of MyClass. Inside that method, I want to create e new instance of T, how can I do that? This doesn't work (because of type erasure): object Demo extends App { def myMethod[T <: MyClass](): Unit = { val t = new T // gives error: class type required by T found } myMethod[MySubclassA]() } abstract class MyClass class MySubclassA extends MyClass class MySubclassB extends MyClass JavaScript questions and answers, JavaScript questions pdf, JavaScript question bank, JavaScript questions and answers pdf, mcq on JavaScript pdf, JavaScript questions and solutions, JavaScript mcq Test , Interview JavaScript questions, JavaScript Questions for Interview, JavaScript MCQ (Multiple Choice Questions)

Answer 1

It fails to work, but not (primarily) because of type erasure, but because your definition should make sense for all T which satisfy the type bounds, and new T doesn't. E.g. T can be MyClass or an abstract subclass, or a subclass without a parameter-less constructor, or a trait (traits can extend classes), or... If a runtime error is good enough, you can go with Sergey Lagutin's solution. But more reasonable for most cases would be to pass some way to create a T to myMethod. Possibly as an implicit argument, e.g. class Factory[T](f: () => T) { def make(): T = f() } object Factory { implicit val MySubclassAFactory = new Factory(() => new MySubclassA) implicit val MySubclassBFactory = new Factory(() => new MySubclassB) } def myMethod[T <: MyClass](implicit factory: Factory[T]): Unit = { val t = factory.make() ... } myMethod[MySubclassA] // works myMethod[MyClass] // compilation error myMethod[ASubclassForWhichFactoryIsNotDefined] // compilation error