ereg/eregi replacement for PHP 5.3 [duplicate]

Question

This question already has answers here: How can I convert ereg expressions to preg in PHP? (4 answers) Closed 2 years ago. I'm sorry to ask a question but I am useless when it comes to understanding regex code. In a php module that I didn't write is the following function function isURL($url = NULL) { if($url==NULL) return false; $protocol = '(http://|https://)'; $allowed = '([a-z0-9]([-a-z0-9]*[a-z0-9]+)?)'; $regex = "^". $protocol . // must include the protocol '(' . $allowed . '{1,63}\.)+'. // 1 or several sub domains with a max of 63 chars '[a-z]' . '{2,6}'; // followed by a TLD if(eregi($regex, $url)==true) return true; else return false; } Can some kind soul give me the replacement code for that with whatever is required to replace the eregi JavaScript questions and answers, JavaScript questions pdf, JavaScript question bank, JavaScript questions and answers pdf, mcq on JavaScript pdf, JavaScript questions and solutions, JavaScript mcq Test , Interview JavaScript questions, JavaScript Questions for Interview, JavaScript MCQ (Multiple Choice Questions)

Answer 1

Good question - this is needed when you upgrade to PHP 5.3, where ereg and eregi functions are deprecated. To replace eregi('pattern', $string, $matches) use preg_match('/pattern/i', $string, $matches) (the trailing i in the first argument means ignorecase and corresponds to the i in eregi - just skip in case of replacing ereg call). But be aware of differences between the new and old patterns! This page lists the main differences, but for more complicated regular expressions you have to look in more detail at the differences between POSIX regex (supported by the old ereg/eregi/split functions etc.) and the PCRE. But in your example, you are just safe to replace the eregi call with: if (preg_match("%{$regex}%i", $url)) return true; (note: the % is a delimiter; normally slash / is used. You have either to ensure that the delimiter is not in the regex or escape it. In your example slashes are part of the $regex so it is more convenient to use different character as delimiter.)