How do I remove the file suffix and path portion from a path string in Bash?

Question

Given a string file path such as /foo/fizzbuzz.bar, how would I use bash to extract just the fizzbuzz portion of said string? JavaScript questions and answers, JavaScript questions pdf, JavaScript question bank, JavaScript questions and answers pdf, mcq on JavaScript pdf, JavaScript questions and solutions, JavaScript mcq Test , Interview JavaScript questions, JavaScript Questions for Interview, JavaScript MCQ (Multiple Choice Questions)

Answer 1

Here's how to do it with the # and % operators in Bash. $ x="/foo/fizzbuzz.bar" $ y=${x%.bar} $ echo ${y##*/} fizzbuzz ${x%.bar} could also be ${x%.*} to remove everything after a dot or ${x%%.*} to remove everything after the first dot. Example: $ x="/foo/fizzbuzz.bar.quux" $ y=${x%.*} $ echo $y /foo/fizzbuzz.bar $ y=${x%%.*} $ echo $y /foo/fizzbuzz Documentation can be found in the Bash manual. Look for ${parameter%word} and ${parameter%%word} trailing portion matching section.