I have to write in MIPS a program that multiplies two number using the add and shift method. After trying many many times, I got somehow a program that I see to should be working, but its not, then I wrote it in Java and the code worked in Java. Then I tried to convert it from Java to MIPS (usually its easier for me to translate to low level language from a code in high level language), and after translating it, still its not working. Here is the code I wrote, and please if anybody detects anything wrong with them or knows how to fix them please do tell me.
Thanks,
In Java:
static int prod = 0;
public static int mult (int mcand, int mier)
{
while (mier != 0)
{
int rem = mier % 2;
if (rem != 0)
{
prod += mcand;
}
mcand = mcand << 1;
mier = mier >> 1;
}
return prod;
}
In MIPS:
# A program that multiplies two integers using the add and shift method
.data # Data declaration section
.text
main: # Start of code section
li $s0, 72 # the multiplicand
li $t0, 72 # the multiplicand in a temporary register
li $s1, 4 # the multiplier
li $t1, 4 # the multiplier in a temporary register
li $s2, 0 # the product
li $s3, 2 # the number 2 in a register for dividing by 2 always for checking if even or odd
LOOP: # first we check if the multiplier is zero or not
beq $t1, $zero, END
div $t1, $s3
mfhi $t3 # remainder is now in register $t3
beq $t3, $zero, CONTINUE # if the current digit is 0, then no need to add just go the shifting part
add $s2, $s2, $t0 # the adding of the multiplicand to the product
CONTINUE: # to do the shifting after either adding or not the multiplicand to the product
sll $t0, $t0, 1
srl $t0, $t0, 1
j LOOP # to jump back to the start of the loop
END:
add $a0, $a0, $s2
li $v0, 1
syscall
# END OF PROGRAM
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