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Calculate the mass percentage of benzene (C6H6) and carbon tetraCHMloride (CCl4) if 22g of benzene is dissoved in 122g of carbon tetraCHMloride. Select the correct answer from above options

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Correct Answer - C6H6=15.28%,CCl4=84.72% Wsol=WC6H6+WCCl4=(22+122)=144g Mass percentage of CCl4= WCCl4 Wsol ×100= 122g 144g ×100 Mass percentage of C6H6= WC6H6 Wsoln ×100= 122 144g ×100 =15.28% Alternatively Mass percentage of C6H6=100-84.72=15.28%

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